On 23 sep, 06:57, "D. S. McNeil" <dsm...@gmail.com> wrote:
> I think replacing 2/3 with 2./3 in
>
> if abs(varia-root)<2/3:
>
> will help a little.. :^) By itself, that cuts the time down to 19s for me.
Slightly better, save yourself doing the same computation over and
over inside all the loops
if abs(varia-root) < 0.67
it is a very little time but adds up quickly over the iterations. Or
if you want to be finer, define the 2./3 as a constant outside of the
loops (with whichever precision you need) and then use the defined
constant inside.
Cheers
Javier
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