On 09/12/2010 06:41 PM, mda_ wrote:
> sage: float(e^(-pi/2))
> 0.20787957635076193
>
> The last digit should be 1, since
> i^i = 0.20787957635076190854........
You could try, e.g.,
sage: (e^(-pi/2)).numerical_approx(100)
0.20787957635076190854695561983
sage: (i^i).numerical_approx(100)
0.20787957635076190854695561983
or
sage: (e^(-pi/2)).n(100)
0.20787957635076190854695561983
sage: (i^i).n(100)
0.20787957635076190854695561983
> sage does not recognize this identity:
>
> sage: e^(-pi/2) == i^i
> e^(-1/2*pi) == I^I
>
> ("True" expected as output.)
This appears to work:
sage: bool(e^(-pi/2) == i^i)
True
> What's the best way to ask sage for floating point approximations; for
> fixed types and unlimited precision types?
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