Jason Grout wrote:
> 1. It seems that once I run the above code, it is impossible for me to
> redefine the function f. For example, running the following gives an
> error the indicates that the first definition of f is still around:
>
> sage: def eval_f(x):
> ... if x.is_zero():
> ... return 0
> ... return sin(x)/x
> ...
> sage: f = function('f',nargs=1, eval_func=eval_f)
> sage: def eval_f(x,t):
> ... if x<0:
> ... return 0
> ... else:
> ... return sin(x+t)/x
> ...
> sage: f=function('f', nargs=2,eval_func=eval_f)
> sage: f(-1,1)
> Traceback (most recent call last):
> ...
> TypeError: Symbolic function f takes exactly 1 arguments (2 given)
It appears that http://trac.sagemath.org/sage_trac/ticket/7490 corrects
this.
Jason
--
Jason Grout
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