A few days ago I posted a query to the jmol mailing list about getting nice mesh lines in jmol that we could make pretty arbitrary, like in http://trac.sagemath.org/sage_trac/attachment/ticket/5511/mesh_function.jpeg (see trac #5511 for the code for that figure). Two people have responded and it looks like we may be making progress; we are now looking for people with ideas about how to make everything work. If you would like to join the discussion (or comment here and I can forward it to the jmol list), please see:
http://www.mail-archive.com/jmol-us...@lists.sourceforge.net/msg13044.html For reference, my initial posting is below. Thanks, Jason I've been using jmol quite a bit lately in Sage for drawing 3d mathematical surfaces. One thing I really miss is the ability to have nice meshes (including arbitrary meshes) on a surface. Currently Jmol allows a mesh option to pmesh surfaces, but that only draws a specific grid that is hard to see (it is the same color as the surface, but lighter or something). Probably the easiest change would be to make the mesh default to black lines (like the black lines for contour plots on cut planes). That would make the mesh lines much easier to see. Seeing the mesh lines often really helps us mathematicians (especially those of us teaching). A very nice functionality to add would be the ability to draw arbitrary meshes on surfaces, similar to what is implemented here (but as black lines on the surface, rather than the crude approximation constructed here): http://trac.sagemath.org/sage_trac/attachment/ticket/5511/mesh_function.jpeg. I think Mathematica has a nice interface to these sorts of things: http://reference.wolfram.com/mathematica/ref/MeshFunctions.html We (Sage) can take care of the interface to draw meshes. What we'd need from jmol is the ability to draw a line *on* a surface and have it look like the contour lines look like on a plane. Maybe for each triangle in the surface, we could give a list of lines to draw on that triangle by specifying (for each line) the two edges the line crosses and the fraction of the distance along the edge to make the intersection between the line and the edge of the triangle. What do you think? Thanks, Jason -- Jason Grout --~--~---------~--~----~------------~-------~--~----~ To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
