Hello all, studying the problem related to desolve and discussed in sage-suppport ( http://groups.google.cz/group/sage-support/browse_thread/thread/b6f6b6f056e80149 ), I have one more question: The function desolve ends with this:
if soln.lhs() == dvar: soln = soln.rhs() So sometimes desolve produces expression (if the solution of ODE has been found in explicit form) and sometimes equation. What is the reason for this behavior? I think that it is confusing for the user, isn't it? Thank you Robert Marik --~--~---------~--~----~------------~-------~--~----~ To post to this group, send an email to sage-devel@googlegroups.com To unsubscribe from this group, send an email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URL: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---