Hi Carl,
On Wed, Jun 10, 2009 at 4:49 PM, Carl Witty<carl.wi...@gmail.com> wrote:
> Is it even possible to use the old typesetting format with the new
> symbolic representation? For example, "df(sin(x)*cos(x))/dx" is
> represented as -(sin(x)^2 - cos(x)^2)*D[0](f)(sin(x)*cos(x)); it seems
> likely to be difficult to invert that to produce
>
> {{{\it \partial}}\over{{\it \partial}\,x}}\,f\left(\cos x\,\sin x \right)
>
> (which is what the old symbolics produced). And what should
> "D[0](f)(sin(x)*cos(x))" be typeset as?
Agree, this is really a mess. If I follow the simple algorithm,
I get "\frac{d f\left(\sin\left(x\right) \cos\left(x\right)\right)}
{d \sin\left(x\right) \cos\left(x\right)}".
Other suggestion (with known pitfalls) could be
"\frac{d f(z)}{d z}_{|z=\sin(x)\cos(x)}" where the argument itself
is an expression.
While using the new representation, I happened to hit a major
drawback. For example: "diff( f(x), x, 20)" is now represented
as
"D[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0](f)(x)"
In seems there are no ways to shorten it.
Also, if I do a copy-n-paste of above expression in a new cell. Sage
doesn't recognize "D" function.
Cheers,
Golam
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