Forgive my stubborness, but you answered only half of my question :)
do you think the following is a sane behavior?
sage: var('f x')
(f, x)
sage: f(x+3)
x+3
I would prefer a NotImplementedError...
Yann
On Feb 26, 11:14 pm, Robert Bradshaw <rober...@math.washington.edu>
wrote:
> On Feb 26, 2009, at 1:15 PM, YannLC wrote:
>
>
>
> > On Feb 26, 9:40 pm, Robert Bradshaw <rober...@math.washington.edu>
> > wrote:
> >> On Feb 26, 2009, at 12:22 PM, YannLC wrote:
>
> >>> Hi,
> >>> am I doing something wrong here?
> >>> If not, this is a bug...
>
> >>> sage: f=function('f',x)
> >>> sage: f
> >>> f(x)
> >>> sage: g(f,x)=f(x+1)
> >>> sage: g
> >>> (f, x) |--> x + 1
>
> >> When one writes g(f, x) it creates two variables f and x, and your
> >> original f is gone. I'm not sure what the best fix is here... There
> >> is also the counter-intuitive
>
> >> sage: f = var('f')
> >> sage: f(3)
> >> 3
>
> >> - Robert
> > My point was unclear.
> > * First, how to define a function 'g' doing what I want then? I mean
> > with an argument which is a function; is it possible?
> > * then, I think that f shouldn't disappear like this:
> > sage: g(f,x)=f(x)
> > sage: g
> > (f, x) |--> x
>
> That can't be done (yet). You can do
>
> def g(f, x):
> return x+1
>
> But then it's a Python function, not a calculus function.
>
> - Robert
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