On Feb 21, 2009, at 3:30 AM, Maurizio wrote: > That was the way I used to do it when I discovered the solution_dict > param. > > So, I started using the dictionaries to do substitution even in > complex expressions... The result was to wait so much time! > > On the contrary, I found that the subs(expr, x=<value>) was SOOOO much > faster (are the dictionaries so slow to deal with?). > > So, I implemented a subList function, where I can pass an expression, > and a list of substitution, in the very same way that the solve() > function returns the results. > > So, now I put all my subsets of numerical values in list like this: > set = [x == 10, y == 20, z == 30, ...] > and do the substitution like this: > result = subList(expr, set) > > Within the function, I just iterate the subs(expr, x = <value>) on the > number of list elements. > > This seems to me much faster than using dictionaries, especially for > complex expressions.
If this is the case, this is clearly a bug. - Robert --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-devel@googlegroups.com To unsubscribe from this group, send email to sage-devel-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-devel URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
