On Fri, May 16, 2008 at 11:58 AM, Robert Bradshaw
<[EMAIL PROTECTED]> wrote:
>
> On May 16, 2008, at 8:57 AM, Nick Alexander wrote:
>
>>
>>> (specifically, sqrt(2) would
>>> be an element of QQ[sqrt(2)] with a specified embedding into RR, so
>>> stuff like RR(1) + sqrt(2) would work).
>>
>> Similar to why matrices are over ZZ rather than QQ: why is sqrt(2) in
>> QQ[sqrt(2)] and not in ZZ[sqrt(2)]?
>
> Good point.

Actually why isn't sqrt(2) in the multiplicative semigroup generated by sqrt(2)?

 -- William

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