Thanks, that's helpful.
G = graphs.GrassmannGraph(5, 4, 2); G
gives 806 vertices, as expected, but why do the vertices seem to have six
points?
G.vertices()[0]
{(0, 0, 0, 1), (1, 0, 0, 1), (1, 0, 0, 2), (1, 0, 0, 4), (1, 0, 0, 0), (1,
0, 0, 3)}
I don't see anything about this in the documentation. Shouldn't it be just
two basis vectors that span the subspace?
Thanks,
Jackson
On Tue, Mar 25, 2025 at 5:33 PM Dima Pasechnik <dimp...@gmail.com> wrote:
> We have functionality to build Grassmann graphs. See GrassmannGraph in
>
> <
> https://doc.sagemath.org/html/en/reference/graphs/sage/graphs/graph_generators.html#sage.graphs.graph_generators.graphgenerators.paleygraph
> >
>
>
> On 25 March 2025 12:46:56 GMT-05:00, Jackson Walters <
> jacksonwalt...@gmail.com> wrote:
>
>> Does Sage support computing Gr_{F_q}(k,r), the space of k-hyperplanes
>> through the origin in GF(q**r)? I looked around for things like Schubert
>> cells and didn't see anything immediately relevant. I've started to write
>> some stuff for k=2. I may do a PR if it's not already available.
>>
>> Thanks,
>> Jackson
>>
>> --
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