Sorry for multiple messages

I just want to say

>sage: p,l,u = a.LU(force=True)
>sage: p
>{'perm_r': [1, 0], 'perm_c': [1, 0]}

It  (  {'perm_r': [1, 0], 'perm_c': [1, 0]}  )  represents transpose and it 
cannot be represented as permutation matrix.
Similar cases may arise for other matrices.

On Tuesday, February 27, 2024 at 11:29:44 PM UTC+5:30 Animesh Shree wrote:

> For transpose :
>
> In  the example we can see permutations are provided as arrays for rows 
> and cols.
> The permutation is equivalent of taking transpose of matrix.
> But we cant represent transpose as a permutation matrix.
>
>
> >>> a = np.matrix([[1,2],[3,5]])
> >>> # a * perm = a.T            
> >>> # perm = a.I * a.T
> >>> a.I*a.T
> matrix([[-1., -5.],
>         [ 1.,  4.]])
> >>>
>
> the output is not permutation matrix. 
>
> On Tuesday, February 27, 2024 at 10:03:25 PM UTC+5:30 Dima Pasechnik wrote:
>
>>
>>
>> On 27 February 2024 15:34:20 GMT, 'Animesh Shree' via sage-devel <
>> sage-...@googlegroups.com> wrote: 
>> >I tried scipy which uses superLU. We get the result but there is little 
>> bit 
>> >of issue. 
>> > 
>> > 
>> >--For Dense-- 
>> >The dense matrix factorization gives this output using permutation 
>> matrix 
>> >sage: a = Matrix(RDF, [[1, 0],[2, 1]], sparse=True) 
>> >sage: a 
>> >[1.0 0.0] 
>> >[2.0 1.0] 
>> >sage: p,l,u = a.dense_matrix().LU() 
>> >sage: p 
>> >[0.0 1.0] 
>> >[1.0 0.0] 
>> >sage: l 
>> >[1.0 0.0] 
>> >[0.5 1.0] 
>> >sage: u 
>> >[ 2.0 1.0] 
>> >[ 0.0 -0.5] 
>> > 
>>
>> you'd probably want to convert the permutation matrix into a permutation. 
>>
>>
>> >--For Sparse-- 
>> >But the scipy LU decomposition uses permutations which involves taking 
>> >transpose, also the output permutations are represented as array. 
>>
>> It is very normal to represent permutations as arrays. 
>> One can reconstruct the permutation matrix from such an array trivially 
>> (IIRC, Sage even has a function for it) 
>>
>> I am not sure what you mean by "taking transpose". 
>>
>> >sage: p,l,u = a.LU(force=True) 
>> >sage: p 
>> >{'perm_r': [1, 0], 'perm_c': [1, 0]} 
>> >sage: l 
>> >[1.0 0.0] 
>> >[0.0 1.0] 
>> >sage: u 
>> >[1.0 2.0] 
>> >[0.0 1.0] 
>> > 
>> > 
>> >Shall I continue with this? 
>>
>> sure, you are quite close to getting it all done it seems. 
>>
>>
>> >On Tuesday, February 6, 2024 at 11:29:07 PM UTC+5:30 Dima Pasechnik 
>> wrote: 
>> > 
>> >> Non-square case for LU is in fact easy. Note that if you have A=LU as 
>> >> a block matrix 
>> >> A11 A12 
>> >> A21 A22 
>> >> 
>> >> then its LU-factors L and U are 
>> >> L11 0 and U11 U12 
>> >> L21 L22 0 U22 
>> >> 
>> >> and A11=L11 U11, A12=L11 U12, A21=L21 U11, A22=L21 U12+L22 U22 
>> >> 
>> >> Assume that A11 is square and full rank (else one may apply 
>> >> permutations of rows and columns in the usual way). while A21=0 and 
>> >> A22=0. Then one can take L21=0, L22=U22=0, while A12=L11 U12 
>> >> implies U12=L11^-1 A12. 
>> >> That is, we can first compute LU-decomposition of a square matrix A11, 
>> >> and then compute U12 from it and A. 
>> >> 
>> >> Similarly, if instead A12=0 and A22=0, then we can take U12=0, 
>> >> L22=U22=0, and A21=L21 U11, 
>> >> i.e. L21=A21 U11^-1, and again we compute LU-decomposition of A11, and 
>> >> then L21=A21 U11^-1. 
>> >> 
>> >> ---------------- 
>> >> 
>> >> Note that in some cases one cannot get LU, but instead must go for an 
>> >> PLU,with P a permutation matrix. 
>> >> For non-square matrices this seems a bit more complicated, but, well, 
>> >> still doable. 
>> >> 
>> >> HTH 
>> >> Dima 
>> >> 
>> >> 
>> >> 
>> >> 
>> >> On Mon, Feb 5, 2024 at 6:00 PM Nils Bruin <nbr...@sfu.ca> wrote: 
>> >> > 
>> >> > On Monday 5 February 2024 at 02:31:04 UTC-8 Dima Pasechnik wrote: 
>> >> > 
>> >> > 
>> >> > it is the matter of adding extra zero rows or columns to the matrix 
>> you 
>> >> want to decompose. This could be a quick fix. 
>> >> > 
>> >> > (in reference to computing LU decompositions of non-square matrices) 
>> -- 
>> >> in a numerical setting, adding extra zero rows/columns may not be such 
>> an 
>> >> attractive option: if previously you know you had a maximal rank 
>> matrix, 
>> >> you have now ruined it by the padding. It's worth checking the 
>> >> documentation and literature if padding is appropriate/desirable for 
>> the 
>> >> target algorithm/implementation. 
>> >> > 
>> >> > -- 
>> >> > You received this message because you are subscribed to the Google 
>> >> Groups "sage-devel" group. 
>> >> > To unsubscribe from this group and stop receiving emails from it, 
>> send 
>> >> an email to sage-devel+...@googlegroups.com. 
>> >> > To view this discussion on the web visit 
>> >> 
>> https://groups.google.com/d/msgid/sage-devel/622a01e0-9197-40c5-beda-92729c4e4a32n%40googlegroups.com
>>  
>> >> . 
>> >> 
>> > 
>>
>

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