Hi Sverre,

I don't think it's a good idea to have different zeroes in an algebraic structure that is also categorized as an abelian group, unless you take the point that a "graded abelian group" should not be an "abelian group".

But let me also point out that something similar to what you want already exists: you can take a homogeneous component of the Steenrod algebra and look at its zero:

   sage: A=SteenrodAlgebra(2)
   sage: A[18]
   Vector space spanned by (Sq(0,1,0,1), Sq(3,0,0,1), Sq(1,1,2),
   Sq(4,0,2), Sq(2,3,1), Sq(5,2,1), Sq(8,1,1), Sq(11,0,1), Sq(0,6),
   Sq(3,5), Sq(6,4), Sq(9,3), Sq(12,2), Sq(15,1), Sq(18)) over Finite
   Field of size 2
   sage: A[18].zero() == A.zero()
   True
   sage: A[18].zero() == A[17].zero()
   False

This suggests that "A[18].zero().degree()" could give 18, and the fact that it currently gives a ValueError might be considered a bug.

Best,
Christian


On 18.07.20 23:35, Sverre Lunøe-Nielsen wrote:
Hi,

Thank you for your comments so far.  I feel I need to expand some more on the issue of zero elements which is the central thing for the problem we are adressing.

It is mathematically equivalent to think of a graded k-algebra A as either

1) a direct sum A = \bigosum_i A_i, together with a graded k-linear map from
   the graded tensor product A\tensor_k A --> A,

or

2) a sequence of k-vectorspaces {A_i}_i, together with a set of structure maps
   \{ A_i \tensor_R A_j --> A_{i+j} \}_{i,j}.

(In both cases the structure maps should satisfy usual algebraic conditions.)

Similar for graded A-modules.

The implementation of the SteenrodAlgebra package takes the approach of 1), and never speaks about the zero element z_i \in A_i for any i.  Rather, they are all identified in A via the canonical injection A_i --> A.  It is tradition not to worry too much about this since you can "figure it out" if you have to, and know how you ended up with a zero.

However, it is arguably better, specially when writing software, to avoid this simplifaction since it leads to a corner case which has to be dealt with over and over again.  A great share of the bugs I have corrected in the package I have been editing have been caused by the wrongful assumption that all elements have an integer degree.  Having not to worry about this would make our code cleaner, and so will all future code building on it.

I was being rather vague about making proposals for change in the SteenrodAlgebra package in my last post, so to be clear let me propose a specific change and invite anyone to share their opinion on it:

Change SteenrodAlgebra such that _all_ homogeneous elements have a well defined degree.  For the user, this means in particular that when constructing the zero element, its degree must be given:

    sage: A = SteenrodAlgebra(p=2)
    sage: z = A.zero(degree=2)
    sage: Sq(1)*Sq(1) == z
    True
    sage: Sq(2)*Sq(1)*Sq(1) == z
    False

This involves adding the degree as internal data to zero elements, and change the behaviour of degree() such that it raises an exception only for inhomogeneous elements.

I hope I have clearified that I am not seeking a strange new definition of graded module or algebra, and that I am merely wanting to discuss the possibility of changing the implementation of SteenrodAlgebra.

E.g. are there perhaps unwanted software ramifications that our proposal would bring about?

Regards,

Sverre





On Saturday, July 18, 2020 at 11:31:43 PM UTC+2, John H Palmieri wrote:



    On Saturday, July 18, 2020 at 2:31:01 AM UTC-7, Sverre
    Lunøe-Nielsen wrote:

        Dear list,

        I have been involved in preparing a package by M. Catanzaro
        and R. Bruner lately, which implements finitely presented
        modules over the mod `p` Steenrod algebra.

        We have encountered a conflict regarding how to present graded
        objects, and I am writing to the list to get other people's
        opinion on how to proceed on this matter.

        Briefly, the issue is that the Steenrod algebra allows
        inhomogeneous elements and our graded modules do not. Thus,
        the Steenrod algebra has a single zero element with no well
        defined degree, while our modules could potentially have one
        zero element for each degree.

        My wish is to allow degreewise zero elements in our graded
        modules, so that x.degree() would return an integer for every
        element x.  But because the unique zero in the Steenrod
        algebra has no well defined degree, I am forced to let
        degree() treat all zero elements in our modules the same way
        and return ``None``.

        A more precise description of the issue is found in the Sphinx
        note below.

        My questions to the list are: Has similar issues been
        discussed and/or resolved before?  And more specificly: What
        acceptable changes could be made to the Steenrod algebra
        package to achieve what I want?

        Regards,

        Sverre Lunøe-Nielsen


        .. NOTE::
        Our implementation treats a graded module as the disjoint
        union, rather than a
        direct sum, of vectorspaces of homogeneous elements. Elements
        are therefore
        always homogeneous, which also implies that sums between
        elements of different
        degrees are not allowed.  This also means that acting by an
        inhomogeneous
        element of the Steenrod algebra makes no sense.

        In this setting there is no single zero element, but rather a
        zero for every
        degree.  It follows that, in theory, all elements, including
        the zero elements,
        have a well defined degree.

        This way of representing a graded object differs from the way
        the graded
        Steenrod algebra is represented by
        :class:`sage.algebras.steenrod` where inhomogeneous
        elements are allowed and there is only a single zero element. 
        Consequently,
        this zero element has no well defined degree.

        Thus, because of the module action, we are forced to follow
        the same convention
        when it comes to the degree of zero elements in a module:  The
        method
        
:meth:`sage.modules.finitely_presented_over_the_steenrod_algebra.module.fp_element.FP_Element.degree'
        returns the value ``None`` for zero elements.

        An example which highlights this problem is the following::

            sage: F = FPA_Module([0], SteenrodAlgebra(p=2))   # The
        free module on a single generator in degree 0.
            sage: g = F.generator(0)
            sage: x1 = Sq(1)*g
            sage: x2 = Sq(1)*x1

        Clearly, the code implementing the module action has all the
        information it needs
        to conclude that the element ``x2`` is the zero element in the
        second degree.
        However, because of the module action, we cannot distinguish
        it from the element::

            sage: x2_ = (Sq(1) * Sq(1))*g

        The latter is equal to the action of the zero element of the
        Steenrod
        algebra on `g`, but since the zero element has no degree in
        the Steenrod algebra,
        the module class cannot deduce what degree the zero element
        `x2_` should belong
        to.


    In my experience, algebraic topologists often think of graded
    objects as disjoint unions, and you can often get away with this,
    but really they're not — they're direct sums. I think you should
    use Sage's categories framework, graded modules with basis or
    whatever, to set these up. In any case where the degree matters,
    you should first test whether an element is zero (in which case it
    won't have a degree) and then perhaps whether it is homogeneous.
    If not, you can raise an error (to keep someone from multiplying a
    module element by Sq(1) + Sq(2), for example). If it is
    homogeneous, you can proceed the way you want.

-- John

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