On 11/1/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> > In particular, how does applying (1,2,3)(4,5) to [0,1,2,3,4]
> > result in what you claim, i.e., in [1, 2, 0, 4, 3]?
> > It should either be an error, or maybe:
> >    [2,0,1,3,4]
> > if say (1,2,3)(4,5) sends the "first entry", i.e., 0th position
> > to the 1st, the 1st to 2nd, etc,
>
> That's what is going on -- I interpret the cycle notation as:
>
> 1 |--> 2
> 2 |--> 3
> 3 |--> 1
> 4 |--> 5
> 5 |--> 4
>
> and I don't know how you arrived at [2,0,1,3,4] -- that looks like (3,2,1) to 
> me.

OK, consider the permutation (1,2,3), which permutes
things as follows:

   1 |--> 2
   2 |--> 3
   3 |--> 1

Thus if the input is v = [a,b,c], then
the output is [c,a,b].   I.e., the permutation sends
the entry at position 1 to position 2, i.e., the a gets
stuck in the middle, the entry at position 2 to position 3,
i.e., the b goes to where c is, and the entry at position 3
goes to the front, i.e., to where a is.  Thus
applied to [0,1,2], we get [2,0,1].

Applying the permutation (1,2,3)(4,5) to [0,1,2,3,4]
should either move the entry in position 1 (which happens
to be called "0") to position 2, so that the output looks like
   [*,0,*,*,*]
or if we do some weird 1-based thing, it would always
fix the first entry, then send the entry in position 1 to
position 2 and look like:
   [0,*,1,*,*]
and neither of these are what you claim, i.e.,
[1, 2, 0, 4, 3].

William

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