On Thu, 01 Nov 2007 00:00:57 -0700, Robert Bradshaw <[EMAIL PROTECTED]> wrote:
> The answer is, I believe, yes. Should it rely on the check flag to
> decide whether or not to try and factor?

Wait, is there a good reason to ever compute the discriminant in order to
represent elements of the field?

Generally, check is supposed to be for checking whether
the polynomial is irreducible or not, which for a quadratic
field Q(sqrt(D)) just means checkin whether D is a perfect
square, which is a lot easier than factoring D.

  -- William

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