On Oct 23, 2007, at 6:51 PM, David Harvey wrote:

> On Oct 23, 2007, at 9:47 PM, William Stein wrote:
>
>>
>> On 10/23/07, David Harvey <[EMAIL PROTECTED]> wrote:
>>>> For huge Z, I wonder if it's still trying to do multi-modular? That
>>>> would probably be bad. I'm also not sure how much of the  
>>>> dispatching
>>>> is done in Linbox vs. Sage.
>>>
>>> Multimodular would be terrible. You don't get any of the benefits of
>>> strassen, since the tiny multiplies are way below the strassen
>>> cutoff. So basically it would end up looking like doing *integer*
>>> multiplication with a multi-modular algorithm, which isn't such a
>>> good idea :-)
>>
>> It's not doing multi-modular unless that matrix is at least 21 x 21
>> *and* the coefficients are relatively small compared to the size
>> of the matrix.    I at least did some tiny amount of tuning for
>> this function (at the airport in Calgary, now that I think about it).
>> Vastly more could be done.
>>
>> I just looked at the code in matrix_modn_dense.pyx for matrix
>> multiply,
>> and we don't use linbox there either yet.  We just use strassen
>> for big matrices and classical multiplication for small matrices.
>
> Actually, soon I will be doing matrix multiply over Z/p^N for some
> large N, so the matrix_modn_dense thing is relevant.
>
> Another question: for large moduli like this, does it delay the
> reduction until after the adds/subs, either in classical or strassen?
> This would mean only O(n^2) reductions instead of O(n^3).

I don't think there is any special code for matrix_mod_n for n larger  
than a word (or perhaps even half a word). For the classical, it  
delays doing reductions when computing the dot product until the last  
moment.

- Robert


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