Craig Citro wrote:
>>> The best I've come up with at this point is, given graphs
>>> A,B,C,D,E, the
>>> union is:
>>>
>>> A.union(B).union(C).union(D).union(E)
>> I actually think that this looks very clear, despite the lack of
>> infix operators.
>>
> 
> I agree -- especially since it looks like a literal translation of  
> the same statement as written mathematics. However, I could see a  
> strong argument that it could get too long -- it wouldn't take much  
> work to change union to support something like this:
> 
> A.union( [ B, C, D, E ] )

I originally was going to do things this way, but then decided the way I 
presented.  However, you're right---it's a trivial change to allow both 
possibilities.  I'll definitely add that.

Thanks,

-Jason


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