Thanks for your answer Wayne, I've run the command with -vvv and got a 13 megs output. ;-)
The file bzipped is just under 1M, I can send to you directly by email if you want. There seems to be certain unsync between the moment this line appears: received request to transfer non-regular file: 86290 [sender] (line number 147370 of output) And the final part (149396 total lines), which is: rsync: connection unexpectedly closed (2245617 bytes received so far) [generator] rsync error: error in rsync protocol data stream (code 12) at io.c(600) [generator=3.0.0] _exit_cleanup(code=12, file=io.c, line=600): about to call exit(12) On Mon, Mar 24, 2008 at 4:14 AM, Wayne Davison <[EMAIL PROTECTED]> wrote: > On Sun, Mar 23, 2008 at 07:54:09PM +0100, Sergi Baila wrote: > > 2008/03/23 19:27:37 [3760] received request to transfer non-regular > file: 86300 [sender] > > This means either that file-list number 86300 is not matching up between > the sender and the receiver, or that the data stream is somehow out of > whack, so the sender misinterpreted what the generator was asking it to > do. I have not seen this failure, so I'll need some more information to > diagnose what is going wrong. An easy way to start to narrow it down is > to run the rsync command with 3 -v options. For each transfer, you'll > see a set of verbose messages, such as: > > recv_generator(byteorder.h,53) > generating and sending sums for 53 > send_files(53, ../rsync/byteorder.h) > > This shows us that the two sides are in sync on both the # and the name. > If you get a failure, send me the tail end of the -vvv output and it > should reveal how things have gone wrong. > > ..wayne.. > -- www.sargue.net
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