>>>>> " " == August Zajonc <[EMAIL PROTECTED]> writes:
> I'd like to simple transfer a list of files with no attempt to
> build up huge file lists. These files will be scattered around
> a directory containing around 500,000 files in total. can I
> simply pass --include-file pointing to the list of files to
> transfer or is something more involved? The problem is that my
> source file list will be complete filenames, ie
> /home/aaa/dir1/file and /home/aaa/dir2/file2 but the
> destination rsync server has a root aaa for /home/aaa.
> The trick is that the files are in a whole bunch of different
> directories, and I can't seem to wrangle it to work with
> something like rsync --include-from=filelist dest.com::aaa
> August
The trick here is to rsync the complete directory but exclude
everything and then include what you need. Confused?
Lets see an example (from the debian rsync mirror script):
rsync $FLAGS $HOST::debian/pool/ --include-from .filelist --exclude '*' $DEST/pool/
This will mirror everything from HOST::debian/pool to DEST/pool, so
there you see how to shorten the path.
But "--exclude '*'" will ignore all files except what has been allowed
by "--include-from .filelist".
Hope that helps,
Goswin
