Alex van den Bogaerdt wrote:

> Complete line:   CDEF:result=A,B,+,C,-,A,B,+,/

Hmm...

Maybe (A+B-C)/(A+B) == (A+B)/(A+B) - C/(A+B) == 1 - C/(A+B)

CDEF:result=1,C,A,B,+,/,-

Saves an instruction :)

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