Guilherme Castelao wrote:
> Hello all,
>
> I'm moving to rpy2 but I still didn't get the new syntax. I have two
> simple questions:
>
>
> - I can create the nls with no trouble as below, but I can't figure
> out how to create the nls.control with rpy2?
>
> model=robjects.r.nls(formula,data=dataf,start=start,control=control,trace=True)
>
It hard to tell without knowing how you created the objects used in the
function call.
>
> - How would be a more elegant way to create a data frame then
>
> d={"x":robjects.FloatVector([4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14]),"y":robjects.FloatVector([4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69])}
> dataf = robjects.r['data.frame'](**d)
>
That way of creating a data.frame is correct, although not the only way.
# with rpy2-2.1.x-dev
import rpy2.robjects as robjects
dataf = robjects.DataFrame(d)
If having to know the type of the R vectors to create is seen as
inelegant, on can put rpy_classic to use:
import rpy2.rpy_classic as rpy
d={"x":rpy.seq2veq([4.17,5.58,5.18,6.11,4.50,4.61,5.17]),
"y":rpy.seq2veq([4.81,4.17,4.41,3.59,5.87,3.83,6.03])}
I have to remind myself to write more about creating data.frames in the
documentation.
L.
> Thanks!
>
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