Hi all, here is my problem,
in R, i can do :
a = matrix(c(1,2,3,4,5,6,7,8,9),ncol=3) #a matrix
> a
[,1] [,2] [,3]
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
> a[dim(a)[1]:1,] #the result i expect
[,1] [,2] [,3]
[1,] 3 6 9
[2,] 2 5 8
[3,] 1 4 7
>
while using rpy , let be :
dimension = sqrt(4**((int)(options.lgMot))) # dimension=16
tmp = r.matrix((1-sigcomp), ncol=dimension) #ok, so now i want to 'flip' the
matrix (sigcomp is a vector)
so i tried :
tmp = tmp[dimension:1,] ==> tmp equals []
tst = r(matrix(tmp, ncol=dimension))
Traceback (most recent call last):
File "./signature.py", line 85, in <module>
tst = r(matrix(tmp, ncol=dimension))
TypeError: __new__() got an unexpected keyword argument 'ncol'
i can't find documentation about an R'lish way to access array in rpy, is there
one ? what did i miss? (using rpy is more likely to help me for the future)
Regards
--
-----------------------------------------------------------------------------------------------
Ludovic MALLET
Équipe Molécules thérapeutiques in-silico (MTi)
Université Paris-Diderot - Inserm U973
Bâtiment Lamarck - 5ème étage, bureau 501
35 rue Hélène Brion - 75205 Paris Cedex 13
tel: 01 57 27 83 91
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