On Wed, Jun 25, 2008 at 5:30 PM, Laurent Gautier <[EMAIL PROTECTED]> wrote:
> 2008/6/25 Sean Davis <[EMAIL PROTECTED]>:
>> First, Laurent, I am giving rpy2 a try and REALLY like what I see so
>> far. It is very much more intuitive, both from the point-of-view of
>> an R programmer as well as for python programmers.
>>
>> Data frames are very nice R data structures, so I would like to
>> capitalize on them and the changes included in rpy2 as much as
>> possible. So, how can I access the members of y (the data.frame)? If
>> one uses list subsetting, the values are actually reversed. I figured
>> out that y.getNames() will return the names of z, which I can then use
>> to determine the list position. Is there a way to do this with the
>> column names directly?
>>
>> In [34]: z = ro.r['data.frame'](x=ro.r.c(1,2,3,4),y=ro.r.c(5,6,7,8))
>>
>> In [35]: z
>> Out[35]:
>> structure(list(y = 5:8, x = 1:4), .Names = c("y", "x"), row.names = c(NA,
>> -4L), class = "data.frame")
>>
>> In [36]: z[0]
>> Out[36]: 5:8
>>
>> In [37]: z[0][1]
>> Out[37]: 6
>>
>> In [38]: z.getNames()
>> Out[38]: c("y", "x")
>>
>
>
> z.subset('y')
> returns a list, because data.frames are R lists, and R lists are
> recursive structures.
>
> z.subset('y')[0]
> should make it.
>
> The method "subset" mimics R's "[". There is probably the need for a
> counterpart to R's "[[".
>
> There will also be a proper class for data.frame (but that will be in July).
Great. I look forward to it! Oh, by the way, I am doing my testing
on R-devel and things are going fine.
Sean
>> Thanks,
>> Sean
>>
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