Calling positional parameter does not work.
the most possible solution is "del r.x"
>>> import rpy
>>> def a(b=0):
... f = open("c:/temp/easy.R","w")
... f.write("sigma <- " + str(b))
... f.close()
...
>>> def k():
... t = "c:/temp/easy.R"
... rpy.r.source(t)
... v = rpy.r.sigma
... del rpy.r.sigma
... return v
...
>>> a()
>>> k()
0.0
>>> a(6)
>>> k()
6.0
>>>
regards,
volkan kepoglu
On 5/5/08, Thomas Juntunen <[EMAIL PROTECTED]> wrote:
>
> On Tue, 29 Apr 2008 10:51:42 +0300, volkan kepoglu wrote:
>
> >>>> def a(b=0):
> > ... f = open("c:/temp/easy.R", "w")
> > ... f.write ("sigma <- " + str(b))
> > ... f.close()
>
> You defined function a() with a named parameter, b, that has a default of
> 0
>
> >>>> a(5) # "sigma <- 5"
>
> You called a() with a positional parameter. Try: a(b=5)
>
>
>
> HTH,
> Thomas Juntunen
>
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