I had to think for a bit: the Fourier transform of a sum is equal to the sum of the terms transformed individually, so the G(r) for a mixture is the weighted sum of G(r) for the components. Brian On Sep 27, 2006, at 9:05 AM, Andy Fitch wrote:
|
- Total scattering/PDF listserv Simon Billinge
- Question Andy Fitch
- Re: Question Brian H. Toby
- Re: Question Alan Hewat
- Re: Question Nicholas Armstrong
- XRD scan of oriented thin films Brajendra Singh
- Re: Question Simon Billinge