Hey,
> I would like to make delly[1] builds reproducible but I'm stuck with no
> idea what the diffoscope log[2] means. I have little to no experience
> with making packages reproducible but like to try my hand at it.
Sure thing. So, one telltale sign in the diffoscope output is the
following hunk:
│ │ │ │ ├── strings --all --bytes=8 {}
│ │ │ │ │ @@ -402,15 +402,15 @@
│ │ │ │ │ GLIBCXX_3.4.29
│ │ │ │ │ CXXABI_1.3
│ │ │ │ │ GLIBCXX_3.4
│ │ │ │ │ -/build/1st/delly-1.0.3/src/htslib/
│ │ │ │ │ +/build/2/delly-1.0.3/2nd/src/htslib/
│ │ │ │ │ AWAVAUATUSH
│ │ │ │ │ []A\A]A^A_
In other words, your /usr/bin/delly binary is embedding the build
path.
Often this is because a package is not obeying CFLAGS/CXXFLAGS etc
from dpkg-buildflags (which contains the magic -ffile-prefix-map=
argument), but looking at the build log I think your package is always
calling g++ in a way that respects this... even when calling Make
recursively here:
.htslib: $(HTSLIBSOURCES)
if [ -r src/htslib/Makefile ]; then cd src/htslib &&
autoheader && autoconf && ./configure --disable-s3
--disable-gcs --disable-libcurl --disable-plugins &&
$(MAKE) && $(MAKE) lib-static && cd ../../ && touch
.htslib; fi
But a quick glance at your package's Makefile suggests that the path
is coming from:
# Submodules
PWD = $(shell pwd)
EBROOTHTSLIB ?= ${PWD}/src/htslib/
... and may very well be related to how the "static-lib" target is
compiled:
# Flags for static compile
ifeq (${STATIC}, 1)
LDFLAGS += -static -static-libgcc -pthread -lhts -lz -llzma -lbz2
else
LDFLAGS += -lhts -lz -llzma -lbz2 -Wl,-rpath,${EBROOTHTSLIB}
endif
^^^^^^^^^^^^^^^^^^^^^^
As package maintainer though, you will probably have more insight into
this; it seems like your package is doing rather interesting things with
this htslib directory. :)
Hope this quick message helps put you on the right path...
Best wishes,
--
o
⬋ ⬊ Chris Lamb
o o reproducible-builds.org 💠
⬊ ⬋
o
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