> RH9
>
> Have a php page and I want the outcome of
>
> du -hs /var/spool/imap/$username | awk '{print $1}'
>
> however, username is (say) joe.user.example.com but the directory is
> joe^user^example^com
>
> Any sed or awk experts help me do this in one line? The output is
> simply the amount of space used by the user.
The answer may not be sed or awk, but tr. Here's a quick test script I
wrote up (I'm sure that somebody could improve upon it):
#!/bin/bash
USERNAME="joe.user.example.com";
du -sh /var/spool/imap/`echo -e $USERNAME | tr [.] [^]` | awk '{print $1}'
HTH
Ben
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