Use awk along wit grep like this:
sensors | grep -i cpu | awk '{print $2}'
this should produce "+53.4?C" given the output you provided.
On Fri, 2003-06-27 at 16:49, Adam Bowns wrote:
> Hello all,
>
> What I am trying to do is run a command and take a very specific part of
> a line of its output and save it to a file. Here's the route i've been
> going down so far... with no success might I add.
>
> the program im running is called sensors (lm_sensors) and run on its own
> gives output of the temperatures of a handful of devices... I've
> narrowed the output down to just the line im interested in with the
> command
>
> sensors |grep CPU: |cat > cpu
>
> which gives me a file called cpu with contents: -
> CPU: +53.4?C (limit = +120?C, hysteresis = +100?C)
>
> the problem im having is that i need the file to just contain: -
> 53.4
>
> or whatever the value was when sensors was run. i've tried variations of
> this command like: -
>
> sensors |grep CPU: |grep -o +##.#? |cat > cpu
>
> but i just cant find a way to get it to do what i want. If any of you
> know the command that will give me the output I'm looking for, or know a
> different way of doing it, that would be fantastic.
>
> Thanks in advance,
> Adam Bowns
>
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