Re: Bash script help ?

[Jan]

Jon Haugsand wrote:

* [EMAIL PROTECTED]

#!/bin/bash
1st_arg=$1

number not allowed in front.

prosesses=`lsof -i`
prosessid=`echo $prosesses | gawk /1st_arg/'{print $2}'`

Cannot understand this to work in gawk.  In any case, you might do
this a lot more effective:

echo $prosessid
if [ -z "$prosessid" ]

missing "then"

echo "not running"
fi

exit 0

Not necessary


My suggestion:

#!/bin/bash
process=`lsof -i | grep $1 | gawk '{print $2 }'`
if [ "$process" = "" ]; then
  echo "not running"
else
  echo $process
fi

Another point is: if you want the PID of the currently processing shell (ie. the one that interprets your script), then according to man bash you can just use the special variable $, like in '$$'.

/jan




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