I use this one at http://www.southwire.com/ProductCatalog/voltdrop.jsp I check the single phase box for DC circuits.

Best,

Greg

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Today's Topics:

   1. Re: calculating DC voltage line loss (Windy Dankoff)
   2. Re: calculating DC voltage line loss (William Miller)
   3. Re: calculating DC voltage line loss (Hugh)


----------------------------------------------------------------------

Message: 1
Date: Sat, 20 Feb 2010 14:05:33 -0700
From: Windy Dankoff <windydank...@mac.com>
To: re-wrenches@lists.re-wrenches.org
Subject: Re: [RE-wrenches] calculating DC voltage line loss
Message-ID: <f0fed95d-d30c-4595-aeda-3e551c634...@mac.com>
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Marco,

Here's another method that you can print to a sheet of paper. I published this in Home Power in 1989 and it's been widely used ever since. So it's an unusual approach, but proven to be consistent with published charts regardless of voltage. It applies to DC and "simple" AC as you'll see.

http://www.conergy.us/PortalData/3/Resources/products/solar_pumps/pdf/wire_sizing_chart.pdf

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Message: 2
Date: Sat, 20 Feb 2010 13:50:14 -0800
From: William Miller <will...@millersolar.com>
To: RE-wrenches <re-wrenches@lists.re-wrenches.org>
Subject: Re: [RE-wrenches] calculating DC voltage line loss
Message-ID: <6.0.1.1.2.20100220134923.03b4d...@millersolar.com>
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Marco:

Installers world wide have commented favorably on the tool we developed. It can be found at: http://millersolar.com/resources/resources.html

William Miller





At 11:48 AM 2/20/2010, you wrote:
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xmlns:ns0="urn:schemas-microsoft-com:office:smarttags">
Can anyone pass on a good website address that provides the means to calculate DC line loss over distance?

The ones that I've come across don't allow for entering in whatever you want as far as specified DC voltage.

Thanks,
marco

f11587.jpg

Marco Mangelsdorf, President
69 Railroad Avenue, A-7
Hilo, Hawai'i 96720
(808) 969-3281, 934-7462 facsimile
<http://www.provisiontechnologies.com>www.provision-solar.com





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Message: 3
Date: Sat, 20 Feb 2010 23:09:51 +0000
From: Hugh <h...@scoraigwind.co.uk>
To: RE-wrenches <re-wrenches@lists.re-wrenches.org>
Subject: Re: [RE-wrenches] calculating DC voltage line loss
Message-ID: <p062309acc7a616496...@[192.168.1.3]>
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Can anyone pass on a good website address that provides the means to calculate DC line loss over distance?


I normally just use the resistivity of copper and make an estimate of the operating temperature. Most of the standard tables that you find in books assume that the temperature of the copper wire is at the limit for PVC insulation (around 70 degrees C) but in reality you will be working much lower (for energy efficiency) and thus have lower resistance.

As usual it's a lot easier for us with metric units of measure (wires are sold according to their cross section in square mm) but you can also do this with AWG. Remember that increasing wire gauge by 3 halves the area, so #6 has half the sectional area, and hence twice the resistance of #3.

Here are some resistances I worked out for an article in HP magazine 134 (back page basics) using "English" units. But here I am giving you the figures at 3 different temperatures to emphasise the effects of temperature:

FEET PER OHM OF TWIN CABLE
===     ===     ===     ===
#AWG    0       35      70 degrees C
===     ===     ===     ===
0        5,541   4,639   3,989
1        4,394   3,679   3,164
2        3,484   2,917   2,509
3        2,763   2,313   1,989
4        2,191   1,835   1,578
5        1,738   1,455   1,251
6        1,378   1,154   992
7        1,093   915     787
8        867     726     624
9        687     575     495
10       545     456     392
12       343     287     247
===     ===     ===     ===

The figures are FEET ONE WAY to make one ohm for a 2-core cable. For example if you use #8 at an operating temperature of 35C then you get 726 feet of wire run (actually using 1452 feet of actual wire) to make one ohm.

It's easy to use. Say your current is I and the wire run is L. Volt-drop will therefore be

        V = I x L / 726 (in this case).

Say 10 amps and 100 feet then you will lose 1000/726 = 1.4 volts.

No sense in calculating a string of decimals, since the temperature is only estimated anyway.

Using this stuff you can build your own spreadsheet or even do the calcs quickly in your head to a useful level of accuracy once you have a bit of experience. As I say its a lot easier with metric units where the wires sizes are multiples of 1 sqmm, and about 28 metres of that stuff is one ohm.

--
Greg Egan

Remote Power Inc.
981 Gold Mine Trail
Fairbanks, AK 99712
P. 907.457.4299

U.S.Distributor for Outback Power Systems and other premium power equipment.

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