If you are just looking to strip the leading namespace from any URI string,
you could do the following:
import re
from rdflib import URIRef
def simplify(term):
return re.sub(r'^.*[#/]', '', str(term)) if isinstance(term, URIRef) else
str(term)
for s,p,o in g.triples( (None, DEFAULT['None'], None) ):
print("{} {} {}".format(simplify(s), simplify(p), simplify(o)))
On Saturday, December 28, 2019 at 9:27:22 AM UTC-5, [email protected]
wrote:
>
> Hello,
>
> I'd like to search a large data set for all terms of a base URI. Can this
> be done with rdflib?
> Something like
> for s,p,o in g.triples( (None, DEFAULT['None'], None) ):
> print("{} {} {}".format(s, p, o))
> ?
>
> And then to split the term, Instead of
> <http://some.default.base/#InterestingTerm>
>
> just
>
> InterestingTerm
>
--
http://github.com/RDFLib
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