The implementation is tricky, but you can understand the distribution
looking at this "alternative" implementation:
(define (myrandom)
#;(/ (+ (random 4294967087) 1) (+ 4294967087 1))
(* (+ (random 4294967087) 1) 2.328306549295728e-10))
[it may have a tiny rounding difference]
Gustavo
Implementation for the current version of Racket (written in C)
https://github.com/racket/racket/blob/master/racket/src/racket/src/newrandom.inc
Implementation a version of Racket in the future (not next version)
(written in Scheme)
https://github.com/racket/racket/blob/master/racket/src/cs/rumble/random.ss
On Tue, Apr 2, 2019 at 2:14 PM <polarish...@gmail.com> wrote:
> Hello everyone,
>
> The specification of `random` function with zero arguments is only that a
> random inexact real numbers between 0 and 1 is generated. I have two quick
> questions about it,
>
> 1. Will all random inexact real numbers between 0 and 1 be eventually
> generated?
> 2. What's the distribution of the numbers generated? Uniformity is a
> little bit ambiguous here because it can mean either each floating-point
> number gets equal chance to be generated or its probability is proportional
> to the interval where real numbers get rounded to it.
>
> Thanks,
> Shaobo
>
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