I thought it was possible to destructure a list in for, but I've been
searching/experimenting for a while without success. I noticed this example
in the docs:
(for ([(i j) #hash(("a" . 1) ("b" . 20))])
(display (list i j)))
So, I assumed I could do this:
(for ([(i j) '(("a" 1) ("b" 20))])
(display (list i j)))
But that doesn't work. I'm trying to avoid something as verbose as:
(for ([(pair) '(("a" 1) ("b" 20))])
(match-let ([(list i j) pair])
(display (list i j))))
Why do elements of a Hash provide 2 values to for, where a 2-tuple list
does not? Is there a more direct way to destructure a list in for?
Thanks,
Brian
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