On Wed, Aug 15, 2018 at 10:08 PM, Alex Gian <alex9...@gmail.com> wrote:

> Normally in match...
>
> > (match '(a b b b b b b a)
>     [`(,x ,y ... ,x) (list 'x: x 'y: y)])
> '(x: a y: (b b b b b b))
>
> > (match '(a b b b b b b d)
>     [`(,x ,y ... ,x) (list 'x: x 'y: y)]
>     [_ 'nope])
> 'nope
>
>
> So far, so good.
> However, in this case:
>
> > (match '(a b b b b b b c)
>     [`(a ,x ... ,y ... ,x ... c) (list 'x: x 'y: y)])
> '(x: (b b b b b b) y: ())
>
> > (match '(a b b b b b b c)
>     [`(a ,x ... ,y ..1 ,x ... c) (list 'x: x 'y: y)])
> '(x: (b b b b b) y: (b))
>
>
'...' is "zero or more" and it looks like it's being greedy.  The pattern
above says to match:

a:  one item
x ...:  as many things as you can (at least zero)
y ...: as many things as you can (at least one)
x ...:  as many things as you can (at least zero)
c: one item

Using greedy matching your first pattern does this:

a gets 'a
x gets '(b b b b b b c)
Match fails!  Nothing to put in y, which must have at least 1 item.
Backtrack.
x gets (b b b b b b)
y gets c
x gets zero items, which is fine
Match fails!  Nothing to put in c, which must have exactly one item.
Backtrack.
x gets (b b b b b)
y gets (b)
c gets c

Match succeeds!  Complete.

>
>
>
> I am confused.  Shouldn't the two instances of 'x ...' be the same?
> In which case, in the first example, 'x' would be '(b b b) and 'y' would
> be '(),
> In the second 'x' would be '(b b) and 'y' would also be '(b b), no?
> That's the way I understand it (and the way it works with most patterns
> matchers I've seen).
>
> What have I missed?
>
>
>
>
>
>
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