Try to start with this:
#lang racket ;; new-lang.rkt
(provide
#%app
#%datum
#%top-interaction
(rename-out
(new-lambda lambda)
(new-mb #%module-begin)))
(define-syntax (new-lambda stx)
(syntax-case stx ()
[(_ (x ...) e ...)
#'(lam '(x ...) '(e ...) (lambda (x ...) e ...))]))
(struct lam (parameters bodies closure) #:property prop:procedure 2)
(define-syntax (new-mb stx)
(syntax-case stx ()
[(_ e ...)
#'(#%module-begin
(let ([v e])
(if (lam? v)
`(lambda ,(lam-parameters v) ,@(lam-bodies v))
v))
...)]))
;; - - -
#lang s-exp "new-lang.rkt” ;; new-lang-client.rkt
((lambda (x) x)
(lambda (y) y))
> On May 23, 2017, at 10:03 PM, Vityou <zlee...@gmail.com> wrote:
>
> On Tuesday, May 23, 2017 at 7:17:18 PM UTC-6, Matthias Felleisen wrote:
>> Why do you interpret S-expressions instead of re-mapping lambda and #%app?
>>
>>
>>
>>
>>
>>> On May 23, 2017, at 9:14 PM, Vityou <zlee...@gmail.com> wrote:
>>>
>>> I might be able to do something like this, but what I'm looking for is
>>> something that will be able to show the variables available to it in
>>> adition to its source. I'll probable have to do something like what you
>>> did with the struct accept add a field with its available variables and
>>> modify #%app to add to its known variables.
>>>
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>
> I dont know what I could map lambda to that would let it retain and print its
> known variables besides a list.
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