The first result string is the first matched string. The second result is what
was matched by the sub expression in the parenthesis.
> Den 4. nov. 2016 kl. 20.04 skrev meino.cra...@gmx.de:
>
> Hi,
>
> Normally I would tend to think, that I am
> quite familiar with regex and their usage
> (background: UNIX?Linux, sed, vi/vim, Perl...)
>
> Then I played a little with regex-match...and
> I have to go to school again..,,
>
> From the Racket guide:
>> (regexp-match #rx"([a-z ]+;)*" "lather; rinse; repeat;")
> '("lather; rinse; repeat;" " repeat;")
>
> [a-z ]: matches one lowercase character of the range of a-z and the #\space
> + : the above one ore more times
> ; : followed by a ';'
> () : all the above grouped
> * : 0 or more times
> seems obvious..
>
> But the result is not (at least for me... ;)
> '("lather; rinse; repeat;" " repeat;")
>
> I understand "lather; rinse; repeat;" as match -
> it reflects the "greedy behaviour" of regex.
>
> But " repeat;" ???
>
> Why not "rinse; repeat;" then???
>
> I am buffled...<scratching my head>
>
> (help!)+
>
> :)
>
> (Thank you)+ (much)+ in advance!
> Cheers
> Meino
>
>
>
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