To use \s as a matcher, you need #px not #rx: (define rx-empty-or-all-blank-string ;#rx"^[[:space:]]*$") #px"^\\s*$")
See http://docs.racket-lang.org/reference/regexp.html?q=pregexp#%28elem._%28rxex._25%29%29 On Friday, October 30, 2015 at 11:15:08 AM UTC-7, Tim Hanson wrote: > hi, > > I must be overlooking something basic, but can't figure out why the second > and third tests here fail. (Makes no difference whether I spell > {space-character} the [[:space:]] or the \\s way.) > > I'd be grateful for enlightenment. :) > > Cheers, > > Tim > > (define rx-empty-or-all-blank-string > ;#rx"^[[:space:]]*$") > #rx"^\\s*$") > > (check-equal? (regexp-match? rx-empty-or-all-blank-string "") #t) > > (check-equal? (regexp-match? rx-empty-or-all-blank-string " \t ") #t) > > (check-equal? (regexp-match? rx-empty-or-all-blank-string " \t\n") #t) -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
