Thank you!

On Fri, Aug 21, 2015 at 2:38 PM, Matthew Flatt <mfl...@cs.utah.edu> wrote:

> At Fri, 21 Aug 2015 12:44:08 -0400, Benjamin Greenman wrote:
> > I'd like to change the result of a 0-arity function, but I need help
> > crafting the right magic spell. Here's my attempt -- this even possible?
> >
> >
> > #lang racket/base
> >
> > (struct wrap (vals)) ;; Wrap a list
> > (define (create) '())
> >
> > (define create-wrap
> >   (impersonate-procedure create
> >     (lambda ()
> >       ;;(values)))) ;; -- this will run, but it doesn't wrap the result
> > like I'd like.
> >       (values (lambda (r) (wrap r))
> >               (values)))))
> >
> > (create-wrap) ;; Error! result arity mismatch: expected 1, got 0.
>
> Just return the result-wrapping function, since that's one result
> (i.e., one more than the zero results for zero arguments):
>
>  #lang racket/base
>
>  (struct wrap (vals)) ;; Wrap a list
>  (define (create) '())
>
>  (define create-wrap
>    (impersonate-procedure create
>      (lambda ()
>        (lambda (r) (wrap r)))))
>
>  (create-wrap)
>
>
>
>
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