Hello everyone, So i am trying to learn scheme in my free time (unfortunately my university doesn't use scheme in their undergraduate courses) and i was comparing the equality operators in gambit and racket and encountered a strange behaviour with the eq? operator in racket. To my surprise comparing the "same" symbol with eq? returns sometimes a different value in the repl. I expected the return value #t.
This is the behaviour: --------------------------- $ racket Welcome to Racket v6.1.1. > (eq? 'l 'l) #f > (eq? 'l 'l) #t > $ racket --no-jit Welcome to Racket v6.1.1. > (eq? 'l 'l) #f > (eq? 'l 'l) #t > (eq? 'l 'l) #f > (eq? 'l 'l) #t > (eq? 'l 'l) #t > (eq? 'l 'l) #t > (eq? 'l 'l) #f > (eq? 'l 'l) #f > --------------------------- How to reproduce this behaviour? Just start racket from the command line and type '(eq? 'l 'l), this should return #f (or sometimes #t). The next time the same expression returns #t. Whats also interesting is that with the command line option --no-jit the return value seems to randomly change between #t and #f. This seems to happen only when you type the expression into the repl. Can someone explain why the eq? operator behaves like this in the racket repl? The eq? operator shows the expected behavior in gambit but not in racket. Do i miss something? Btw a big thank you to the racket team for developing, maintaining and improving racket. Racket is awesome. -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
