Hello,
The `show' function above exercise 50 in HTDP2e draft (or exercise 52 in
HTDP2e) is:
(define (show x)
(cond
[(string? x) ...]
[(<= -3 x -1) ...]
[(>= x 0) ...]))
(in section 4.5)
The third clause perfectly expresses the non-negative condition of LRCD.
However, exercise 50 still asks to write "a completely accurate condition for"
the third clause.
According to the paragraph below the `show' function, which says "(> x 0) is a
test for all non-negative numbers", and the exercise 50, I suspect the author
was trying to write `[(> x 0) ...]' in the book. Please correct me if I am
wrong.
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