For the testing program provided by Matthew, we can also use *(timeline v)* (an enhanced version of displayln) to compare the value of v at each iteration and see the results in a better way:
If you want to try it out yourself, you can go to https://github.com/lixiangqi/medic and install the Medic package which has support for timeline. By writing the following Medic program, #lang medic (layer layer1 (in #:module "src.rkt" [(at (+ v (/ x 100))) [on-entry (timeline v)]] [(at (+ v (/ x (- 100 x)))) [on-entry (timeline v)]])) you'll see a timeline view of results. Xiangqi On Sat, Jan 24, 2015 at 09:56 AM, Matthew Flatt <mfl...@cs.utah.edu> wrote: > > Jens Axel and Alexander have provided the answer, but in case it helps > to see what they mean, try these loops that display the intermediate > results: > > (for/fold ([v 0]) ([x (in-range 100)]) > (displayln v) > (+ v (/ x 100))) > > (for/fold ([v 0]) ([x (in-range 100)]) > (displayln v) > (+ v (/ x (- 100 x)))) > >
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