All, I am sure this question has been answered before, but I can't find it. Suppose I want to call some function, either built-in or user-defined, n number of times, and measure the total time it takes. Is there a more efficient or elegant way of doing this than passing the expression to a tail-recursive counting loop such as the following?
(define (repeater sexpr count) (sexpr) (cond [(> count 0) (repeater sexpr (- count 1)) ]) ) George Rudolph Associate Professor of Computer Science Department of Mathematics and Computer Science 225 Thompson Hall The Citadel 171 Moultrie Street Charleston, SC 29409 843.953.5032
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