Not sure that's what you really want, but you can use a simple macro to get both the procedure and the corresponding string when defining the procedure:
#lang racket ;; Macro: (define-syntax-rule (lambda+string args body ...) (values (lambda args body ...) (~a '(lambda args body ...)))) ;; Example: (define-values (foo foo-str) (lambda+string (x y) (+ x y 3))) ;; Tests: (foo 3 4) foo-str If you want to get the body of an existing procedure, I don't know of any other way that search for the procedure in the source file and extract it from there, which is not a trivial matter and not 100% possible. Laurent On Mon, Dec 30, 2013 at 4:45 AM, Alegria Baquero <alegriabaqu...@gmail.com>wrote: > Hello, > > is there any way to transform a function's body to a string such as > "(lambda(x)...)"? > > Thanks > > Alegria > > ____________________ > Racket Users list: > http://lists.racket-lang.org/users > >
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