Two hours ago, Neil Van Dyke wrote:
> If I want to have a procedure or syntax that evaluates a block of
> code with a timeout, and it needs to be perfectly reliable[*], then
> is the below "call-with-timeout" procedure the way to do it?
> [...]
Not a direct answer -- but did you consider `call-with-limits'? IIUC,
you could do something like this:
(define (call-with-timeout ... same ...)
(with-handlers ([exn:fail:resource?
(if timeout-proc (λ(e) (timeout-proc)) void)])
(call-with-limits timeout-seconds #f proc)))
--
((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://barzilay.org/ Maze is Life!
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