Hi, I'm super new to Racket, but had what I hope isn't too embarrassingly easy of a question.
I'm writing a program that parses SMTP headers in order to automate some business-y workflow. I managed to put together a series of "regexp-match*"s to parse out the specific identifiers I was looking for (although truth be told, mail headers are surprisingly nonstandard even within a single message), and ran into an error later when trying to string-append them. I eventually discovered by process of elimination (after trying string?, etc. to figure out how the results of a regexp are stored) that they were a list. I tried list->string and a few other methods to covert them, but wasn't having any luck. I eventually discovered that I could sort of cheat, by just wrapping the regexp-match function with a car (which worked, because this particular list only had one element), and then it was usable from then on (and validated true from "string?"). So, my actual question is two-fold. First, It seems like I must have missed some pretty obvious way to capture the initial regex match as a string, but I'm not sure what it was. And secondly, and actually what I'm more curious about, why does it become a string when wrapped by car? I would have presumed that car would leave structures as a list. Again, I apologize if this is something dead-simple, but I really did spend a good portion of the day stuck in "regex-hell", and so was curious. -Chris ____________________ Racket Users list: http://lists.racket-lang.org/users
