Regexp question: Is there a way using regexp only to return a list with a single element? I could use a Racket list function such as caar to return the second element but I am wondering if there is a way to do this using regexp only.
For example this regexp-match function generates the "b" that I want but it is the second element in the list. It would be ideal, from my perspective, if that was all it generated. Is there a way to write the regexp-match expression so that '("b") is output? I get this: (regexp-match #rx"\"(.*)" "a\"b") ; => '("\"b" "b") I'd prefer: (regexp... "a\"b" ) ; => '("b") Thanks. Don Green
____________________ Racket Users list: http://lists.racket-lang.org/users