Alan Johnsey wrote at 04/25/2013 10:04 PM:
(define x (make-posn 4 5))(define y (make-posn 4 5))
[...]
> (equal? x y) #f
[...]
Adding #:transparent to the posn struct definition makes x equal? to both y and z as it should, and eq? gives #f when comparing x and y as it should.
Seems good for security that one can't use "equal?" and constructor brute-force to determine the contents of an opaque struct.
Neil V.
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