On Sep 13, 2012, at 10:22 AM, Ashley Fowler wrote: > I have to write a procedure (cube-two X Y) that takes two numeric arguments > and returns a list of their cubes. > > So far I have... > > (define cube(lambda(x)(* x x x)))...which takes ONE numeric > arguments...example below... > > (cube 3) ==> ( 27) > > > How could I make it to take two numeric arguments? > > For instance... > > (cube-two 1 4) ==> (1 64) > (cube-two 2 5) ==> (8 125)
Well, it sounds like you've already done a big chunk of the work, by implementing 'cube'. Your best bet here is to *use* cube in order to define your cube-two function. Are you using the HtDP textbook? This would be a great time to write down a purpose statement and header. John
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