There is char->integer, but it produces the character's number in Unicode, so #\1 would not map to 1. You may be best off in that case with (string->number (string ch)) for any character ch.
Carl Eastlund On Mon, Sep 10, 2012 at 1:19 PM, Gregory Woodhouse <gregwoodho...@me.com>wrote: > Is there a similar function for characters? I.e., one that will map #\1 to > 1? > > Sent from my iPhone > > On Sep 10, 2012, at 9:44 AM, Carl Eastlund <c...@ccs.neu.edu> wrote: > > The following expression should do what you want: > > (+ (string->number "1.2") 1) > > If you're starting from a symbol, use symbol->string before string->number. > > Carl Eastlund > > On Mon, Sep 10, 2012 at 12:41 PM, Nikolaus Klepp <dr.kl...@gmx.at> wrote: > >> Hi all, >> >> In tinyscheme I can do this: >> >> > (+ (string->symbol "1.2") 1) >> 2.2 >> >> In racket that does not work, because >> >> > (string->symbol "1.2") >> '|1.2| >> >> which is not a number. I can use this workaround: >> >> > (+ (read (open-input-string "1.2")) 1) >> 2.2 >> >> But is there a clean way to get the above line from tinyscheme working on >> racket without that workaround? >> >> Nik >> >> ____________________ > Racket Users list: > http://lists.racket-lang.org/users > >
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