On 08/13/2012 04:41 PM, Marco Alberti wrote:
Erik,On Sun, 12 Aug 2012 12:32:53 +0700, Erik Dominikus wrote:(define %a (%rel (x) ((x) (%b x) !) ((x) (%c x)) ))the cut in the first clause is not there in the Prolog version; hence the different behaviour.
The problem exists even if you remove this cut. The other cut (in %b) is still behaving incorrectly.
(I assume that's what Matthias meant in his recent response.) Ryan ____________________ Racket Users list: http://lists.racket-lang.org/users
