I had this conversation with DrRacket 5.2: > (procedure-arity (compose1 (lambda (x) 0) (lambda () 0))) (arity-at-least 0)
> (procedure-arity (compose1 (lambda (x) 0) (lambda (x) 0))) 1 > (procedure-arity (compose1 (lambda (x) x) (lambda (x y) 0))) (arity-at-least 0) I think the arity of the first procedure above should be exactly 0 since (arity-at-least 0) means that the procedure can take 0, 1, 2, 3 arguments and so on, and indeed DrRacket says that it can't: > ((compose1 (lambda (x) 0) (lambda () 0)) 0) #<procedure>: expects no arguments, given 1: 0 By the same way of thought, I think the arity of the third procedure should be exactly 2. Am I missing something? ____________________ Racket Users list: http://lists.racket-lang.org/users
